Optimal. Leaf size=188 \[ \frac{4 e^3}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos ^3(c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos (c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{4 e}{a^2 d \sqrt{e \sin (c+d x)}}+\frac{16 e \cos (c+d x)}{5 a^2 d \sqrt{e \sin (c+d x)}}+\frac{28 E\left (\left .\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{5 a^2 d \sqrt{\sin (c+d x)}} \]
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Rubi [A] time = 0.589679, antiderivative size = 188, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 9, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.36, Rules used = {3872, 2875, 2873, 2567, 2636, 2640, 2639, 2564, 14} \[ \frac{4 e^3}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos ^3(c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos (c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{4 e}{a^2 d \sqrt{e \sin (c+d x)}}+\frac{16 e \cos (c+d x)}{5 a^2 d \sqrt{e \sin (c+d x)}}+\frac{28 E\left (\left .\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{5 a^2 d \sqrt{\sin (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2875
Rule 2873
Rule 2567
Rule 2636
Rule 2640
Rule 2639
Rule 2564
Rule 14
Rubi steps
\begin{align*} \int \frac{\sqrt{e \sin (c+d x)}}{(a+a \sec (c+d x))^2} \, dx &=\int \frac{\cos ^2(c+d x) \sqrt{e \sin (c+d x)}}{(-a-a \cos (c+d x))^2} \, dx\\ &=\frac{e^4 \int \frac{\cos ^2(c+d x) (-a+a \cos (c+d x))^2}{(e \sin (c+d x))^{7/2}} \, dx}{a^4}\\ &=\frac{e^4 \int \left (\frac{a^2 \cos ^2(c+d x)}{(e \sin (c+d x))^{7/2}}-\frac{2 a^2 \cos ^3(c+d x)}{(e \sin (c+d x))^{7/2}}+\frac{a^2 \cos ^4(c+d x)}{(e \sin (c+d x))^{7/2}}\right ) \, dx}{a^4}\\ &=\frac{e^4 \int \frac{\cos ^2(c+d x)}{(e \sin (c+d x))^{7/2}} \, dx}{a^2}+\frac{e^4 \int \frac{\cos ^4(c+d x)}{(e \sin (c+d x))^{7/2}} \, dx}{a^2}-\frac{\left (2 e^4\right ) \int \frac{\cos ^3(c+d x)}{(e \sin (c+d x))^{7/2}} \, dx}{a^2}\\ &=-\frac{2 e^3 \cos (c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos ^3(c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{\left (2 e^2\right ) \int \frac{1}{(e \sin (c+d x))^{3/2}} \, dx}{5 a^2}-\frac{\left (6 e^2\right ) \int \frac{\cos ^2(c+d x)}{(e \sin (c+d x))^{3/2}} \, dx}{5 a^2}-\frac{\left (2 e^3\right ) \operatorname{Subst}\left (\int \frac{1-\frac{x^2}{e^2}}{x^{7/2}} \, dx,x,e \sin (c+d x)\right )}{a^2 d}\\ &=-\frac{2 e^3 \cos (c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos ^3(c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}+\frac{16 e \cos (c+d x)}{5 a^2 d \sqrt{e \sin (c+d x)}}+\frac{2 \int \sqrt{e \sin (c+d x)} \, dx}{5 a^2}+\frac{12 \int \sqrt{e \sin (c+d x)} \, dx}{5 a^2}-\frac{\left (2 e^3\right ) \operatorname{Subst}\left (\int \left (\frac{1}{x^{7/2}}-\frac{1}{e^2 x^{3/2}}\right ) \, dx,x,e \sin (c+d x)\right )}{a^2 d}\\ &=\frac{4 e^3}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos (c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos ^3(c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{4 e}{a^2 d \sqrt{e \sin (c+d x)}}+\frac{16 e \cos (c+d x)}{5 a^2 d \sqrt{e \sin (c+d x)}}+\frac{\left (2 \sqrt{e \sin (c+d x)}\right ) \int \sqrt{\sin (c+d x)} \, dx}{5 a^2 \sqrt{\sin (c+d x)}}+\frac{\left (12 \sqrt{e \sin (c+d x)}\right ) \int \sqrt{\sin (c+d x)} \, dx}{5 a^2 \sqrt{\sin (c+d x)}}\\ &=\frac{4 e^3}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos (c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{2 e^3 \cos ^3(c+d x)}{5 a^2 d (e \sin (c+d x))^{5/2}}-\frac{4 e}{a^2 d \sqrt{e \sin (c+d x)}}+\frac{16 e \cos (c+d x)}{5 a^2 d \sqrt{e \sin (c+d x)}}+\frac{28 E\left (\left .\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{5 a^2 d \sqrt{\sin (c+d x)}}\\ \end{align*}
Mathematica [C] time = 1.32651, size = 222, normalized size = 1.18 \[ \frac{4 \cos ^4\left (\frac{1}{2} (c+d x)\right ) \sec ^2(c+d x) \sqrt{e \sin (c+d x)} \left (\frac{3}{4} \sec (c) \left (49 \sin \left (\frac{1}{2} (c-d x)\right )+35 \sin \left (\frac{1}{2} (3 c+d x)\right )-23 \sin \left (\frac{1}{2} (c+3 d x)\right )+5 \sin \left (\frac{1}{2} (5 c+3 d x)\right )\right ) \sec ^3\left (\frac{1}{2} (c+d x)\right )+\frac{56 i e^{2 i c} \left (3 \text{Hypergeometric2F1}\left (-\frac{1}{4},\frac{1}{2},\frac{3}{4},e^{2 i (c+d x)}\right )+e^{2 i d x} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{3}{4},\frac{7}{4},e^{2 i (c+d x)}\right )\right )}{\left (1+e^{2 i c}\right ) \sqrt{1-e^{2 i (c+d x)}}}\right )}{15 a^2 d (\sec (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.688, size = 205, normalized size = 1.1 \begin{align*}{\frac{1}{d} \left ( -2\,{\frac{e}{{a}^{2}} \left ( 2\,{\frac{1}{\sqrt{e\sin \left ( dx+c \right ) }}}-2/5\,{\frac{{e}^{2}}{ \left ( e\sin \left ( dx+c \right ) \right ) ^{5/2}}} \right ) }-{\frac{2\,e}{5\,{a}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}\cos \left ( dx+c \right ) } \left ( 14\,\sqrt{-\sin \left ( dx+c \right ) +1}\sqrt{2+2\,\sin \left ( dx+c \right ) } \left ( \sin \left ( dx+c \right ) \right ) ^{7/2}{\it EllipticE} \left ( \sqrt{-\sin \left ( dx+c \right ) +1},1/2\,\sqrt{2} \right ) -7\,\sqrt{-\sin \left ( dx+c \right ) +1}\sqrt{2+2\,\sin \left ( dx+c \right ) } \left ( \sin \left ( dx+c \right ) \right ) ^{7/2}{\it EllipticF} \left ( \sqrt{-\sin \left ( dx+c \right ) +1},1/2\,\sqrt{2} \right ) +9\, \left ( \sin \left ( dx+c \right ) \right ) ^{5}-11\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}+2\,\sin \left ( dx+c \right ) \right ){\frac{1}{\sqrt{e\sin \left ( dx+c \right ) }}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{e \sin \left (d x + c\right )}}{{\left (a \sec \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{e \sin \left (d x + c\right )}}{a^{2} \sec \left (d x + c\right )^{2} + 2 \, a^{2} \sec \left (d x + c\right ) + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\sqrt{e \sin{\left (c + d x \right )}}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec{\left (c + d x \right )} + 1}\, dx}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{e \sin \left (d x + c\right )}}{{\left (a \sec \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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